Consensus Won β
Smart money consensus was Kristjan Tamm β and it was correct. Winning outcome: Kristjan Tamm

M15 Maanshan: Seongchan Hong vs Kristjan Tamm
Resolved Kristjan Tamm. 57% of the top Polymarket traders held Kristjan Tamm. The smart money was right.
π
Won
7
Kristjan Tamm 57%
$2.1K
$159.42
Smart Money Signal
4 of 7 top traders (57%)3 hold an outcome priced under 50%4 small positions dimmed (<$100 invested)
Outcome Probabilities
Smart Money Breakdown by Outcome
| Trader | Position | Invested | Value | PnL | Record |
|---|---|---|---|---|---|
LO looppau | Kristjan Tammavg 99.9Β’ | $1.5K | $1.5K | +$32.25 | 99% 12947-106 (13053) |
![]() RN1 | Kristjan Tammavg 22.7Β’ | $122.31 | $539.67 | +$417.36 | 53% 62265-54490 (116755) |
MA MarquisDeMott<$100 | Kristjan Tammavg 99.1Β’ | $76.3 | $77 | +$0.69 | 98% 3759-90 (3849) |
OM omnibus-076daaCTR | Seongchan Hongavg 45.3Β’ | $234.25 | β | -$234.25 | 50% 21530-21816 (43346) |
PA Pan9X<$100 | Kristjan Tammavg 18Β’ | $4.5 | $25 | +$20.5 | 54% 10426-8742 (19168) |
0X 0xdbdd45150249e229eB4cA8aa48A30Dca21Faa5de-1757094771846CTR<$100 | Seongchan Hongavg 70.6Β’ | $53.64 | β | -$50.18 | 59% 33206-23372 (56578) |
38 38791873984189CTR<$100 | Seongchan Hongavg 77Β’ | $26.95 | β | -$26.95 | 48% 62365-67229 (129594) |
Invested
$1,498.5
Value
$1.5K
PnL
+$32.25
Record
99%
12947-106 (13053)
RN1Invested
$122.31
Value
$539.67
PnL
+$417.36
Record
53%
62265-54490 (116755)
Invested
$76.3
Value
$77
PnL
+$0.69
Record
98%
3759-90 (3849)
Invested
$234.25
Value
β
PnL
-$234.25
Record
50%
21530-21816 (43346)
Invested
$4.5
Value
$25
PnL
+$20.5
Record
54%
10426-8742 (19168)
Invested
$53.64
Value
β
PnL
-$50.18
Record
59%
33206-23372 (56578)
Invested
$26.95
Value
β
PnL
-$26.95
Record
48%
62365-67229 (129594)
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Market Info
Traders in this Market
looppau
Kristjan Tamm β $1.5K

RN1
Kristjan Tamm β $539.67
MarquisDeMott
Kristjan Tamm β $77
omnibus-076daa
CTRSeongchan Hong β $0
Pan9X
Kristjan Tamm β $25
0xdbdd45150249e229eB4cA8aa48A30Dca21Faa5de-1757094771846
CTRSeongchan Hong β $0
38791873984189
CTRSeongchan Hong β $0